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lat:homework [2009/11/27 22:50]
barbara.jobstmann
lat:homework [2009/11/27 22:51]
barbara.jobstmann
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 ====== LAT Homework ====== ====== LAT Homework ======
  
-===== 02.10.2009=====+===== 02.10.2009 =====
  ​Consider the automata construction from proof of the Myhill-Nerode theorem for a language L. Prove   ​Consider the automata construction from proof of the Myhill-Nerode theorem for a language L. Prove 
   * (a) the constructed automaton A is the minimal automaton (in the number of states) that recognizes L;   * (a) the constructed automaton A is the minimal automaton (in the number of states) that recognizes L;
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-== 06.11.2009== +===== 06.11.2009 ​=====
      - Given a reachability game (G,F), give an algorithm that computes the 0-Attractor(F) set in time O(|E|).      - Given a reachability game (G,F), give an algorithm that computes the 0-Attractor(F) set in time O(|E|).
      - Consider the game graph shown in below and the following winning conditions: a) Occ(ρ) ∩ {1} ≠ ∅ and b) Occ(ρ) ⊆ {1,​2,​3,​4,​5,​6} and c) Inf(ρ) ∩ {4,5} ≠ ∅. Compute the winning regions and corresponding winning strategies showing the intermediate steps (i.e., the Attractor and Recurrence sets) of the computation.      - Consider the game graph shown in below and the following winning conditions: a) Occ(ρ) ∩ {1} ≠ ∅ and b) Occ(ρ) ⊆ {1,​2,​3,​4,​5,​6} and c) Inf(ρ) ∩ {4,5} ≠ ∅. Compute the winning regions and corresponding winning strategies showing the intermediate steps (i.e., the Attractor and Recurrence sets) of the computation.
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        - If f<​sub>​0</​sub>​ is a winning strategy for Player 0 in the safety game for (G,​W<​sub>​0</​sub>​),​ then f<​sub>​0</​sub>​ is also a winning strategy for Player 0 in the Buchi game for (G,​F),  ​        - If f<​sub>​0</​sub>​ is a winning strategy for Player 0 in the safety game for (G,​W<​sub>​0</​sub>​),​ then f<​sub>​0</​sub>​ is also a winning strategy for Player 0 in the Buchi game for (G,​F),  ​
        - the winning set of Player 1 in the guaranty game for (G,W_1) is W_1, and         - the winning set of Player 1 in the guaranty game for (G,W_1) is W_1, and 
-       - if f_1 is a winning strategy for Player 1 in the guaranty game for (G,​W<​sub>​0</​sub>​),​ then f_1 is a winning strategy in the Buchi game (G,​F). ​{{hw1.gif|Figure 1}}+       - if f_1 is a winning strategy for Player 1 in the guaranty game for (G,​W<​sub>​0</​sub>​),​ then f_1 is a winning strategy in the Buchi game (G,​F). ​
  
-== 13.11.2009==+{{hw1.gif|Figure 1}} 
 + 
 +===== 13.11.2009 ​=====
      - Consider the game graph shown below. ​ Let the winning condition for Player 0 be Occ(ρ)={1,​2,​3,​4,​5,​6,​7}      - Consider the game graph shown below. ​ Let the winning condition for Player 0 be Occ(ρ)={1,​2,​3,​4,​5,​6,​7}
         - Find the winning region for Player 0 and describe a winning strategy         - Find the winning region for Player 0 and describe a winning strategy
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      - A winning strategy is called "​uniform"​ if it is a winning strategy from every winning state in the game.  Let (G,p) be a weak parity game and let W<​sub>​0</​sub>​ be the winning region of Player 0. For all s ∈ W<​sub>​0</​sub>​ let f_s be a positional winning strategy from s for Player 0. Construct a uniform winning strategy f from the strategies f_s meaning that for every s ∈ W<​sub>​0</​sub>​ there is a t ∈ W<​sub>​0</​sub>,​ s.t. f(s) = f_t(s).      - A winning strategy is called "​uniform"​ if it is a winning strategy from every winning state in the game.  Let (G,p) be a weak parity game and let W<​sub>​0</​sub>​ be the winning region of Player 0. For all s ∈ W<​sub>​0</​sub>​ let f_s be a positional winning strategy from s for Player 0. Construct a uniform winning strategy f from the strategies f_s meaning that for every s ∈ W<​sub>​0</​sub>​ there is a t ∈ W<​sub>​0</​sub>,​ s.t. f(s) = f_t(s).
  
-== 27.11.2009==+===== 27.11.2009 ​=====
      - Consider the game graph below and the Muller condition F={{2,​4,​5,​7},​{1,​2,​3,​4,​5,​6,​7}}. Find an automaton winning strategy for Player 0 in the Muller game with as few states as possible and show that any other automaton strategy with less states is not winning for Player 0. {{hw4.gif}}      - Consider the game graph below and the Muller condition F={{2,​4,​5,​7},​{1,​2,​3,​4,​5,​6,​7}}. Find an automaton winning strategy for Player 0 in the Muller game with as few states as possible and show that any other automaton strategy with less states is not winning for Player 0. {{hw4.gif}}
      - Consider the game shown on page 6 of {{slide10.pdf}}. We propose the following "​latest appearance queue" (LAQ) strategy for Player 0, initializing the queue with s<​sub>​1</​sub>​s<​sub>​2</​sub>​s<​sub>​3</​sub>​s<​sub>​4</​sub>,​ (1) add the current state at the front of the LAQ and delete the last state (2) move to the state t<​sub>​i</​sub>​ whose number i is the number of different states in the current LAQ, e.g., for the sequence of states s<​sub>​1</​sub>,​ s<​sub>​3</​sub>,​ s<​sub>​3</​sub>,​ s<​sub>​4</​sub>,​ s<​sub>​1</​sub>,​... we obtain the following sequence of LAQs: s<​sub>​1</​sub>​s<​sub>​2</​sub>​s<​sub>​3</​sub>​s<​sub>​4</​sub>,​ s<​sub>​1</​sub>​s<​sub>​1</​sub>​s<​sub>​2</​sub>​s<​sub>​3</​sub>,​ s<​sub>​3</​sub>​s<​sub>​1</​sub>​s<​sub>​1</​sub>​s<​sub>​2</​sub>,​ s<​sub>​3</​sub>​s<​sub>​3</​sub>​s<​sub>​1</​sub>​s<​sub>​1</​sub>,​ s<​sub>​4</​sub>​s<​sub>​3</​sub>​s<​sub>​3</​sub>​s<​sub>​1</​sub>,​s<​sub>​1</​sub>​s<​sub>​4</​sub>​s<​sub>​3</​sub>​s<​sub>​3</​sub>,​... ​    ​Decide wheater the new LAQ strategy is a winning strategy for Player 0. Prove this or give a counter-example.      - Consider the game shown on page 6 of {{slide10.pdf}}. We propose the following "​latest appearance queue" (LAQ) strategy for Player 0, initializing the queue with s<​sub>​1</​sub>​s<​sub>​2</​sub>​s<​sub>​3</​sub>​s<​sub>​4</​sub>,​ (1) add the current state at the front of the LAQ and delete the last state (2) move to the state t<​sub>​i</​sub>​ whose number i is the number of different states in the current LAQ, e.g., for the sequence of states s<​sub>​1</​sub>,​ s<​sub>​3</​sub>,​ s<​sub>​3</​sub>,​ s<​sub>​4</​sub>,​ s<​sub>​1</​sub>,​... we obtain the following sequence of LAQs: s<​sub>​1</​sub>​s<​sub>​2</​sub>​s<​sub>​3</​sub>​s<​sub>​4</​sub>,​ s<​sub>​1</​sub>​s<​sub>​1</​sub>​s<​sub>​2</​sub>​s<​sub>​3</​sub>,​ s<​sub>​3</​sub>​s<​sub>​1</​sub>​s<​sub>​1</​sub>​s<​sub>​2</​sub>,​ s<​sub>​3</​sub>​s<​sub>​3</​sub>​s<​sub>​1</​sub>​s<​sub>​1</​sub>,​ s<​sub>​4</​sub>​s<​sub>​3</​sub>​s<​sub>​3</​sub>​s<​sub>​1</​sub>,​s<​sub>​1</​sub>​s<​sub>​4</​sub>​s<​sub>​3</​sub>​s<​sub>​3</​sub>,​... ​    ​Decide wheater the new LAQ strategy is a winning strategy for Player 0. Prove this or give a counter-example.